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JAMB 1983 · UME · Q31

A rod of length 250 cm is measured as 255 cm. What is the percentage error in the measurement?

Worked solution (try it first)
  1. The error is the difference between the measured and true lengths: 255−250=5255 - 250 = 5 cm.
  2. Percentage error is the error as a percentage of the true value: 5250×100%\frac{5}{250} \times 100\%.
  3. 5250=0.02\frac{5}{250} = 0.02, so the percentage error is 2%, option E.

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