JAMB 1983 · UME · Q33

Logarithms

Without using tables, find the numerical value of $\log_7 49 + \log_7\frac17$ .

Worked solution (try it first)

$49 = 7^2$ , so $\log_7 49 = 2$ .
$\frac17 = 7^{-1}$ , so $\log_7 \frac17 = -1$ .
So the value is $2 + (-1) = 1$ , option A.

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