JAMB 1983 · UME · Q50

A man drove for 4 hours at a certain speed; he then doubled his speed and drove for another 3 hours. Altogether he covered 600 km. At what speed did he drive for the last 3 hours?

Worked solution (try it first)
  1. Let the first speed be vv km/h.
  2. Distance is speed times time, so the first part is 4v4v km and the second, at 2v2v for 3 hours, is 6v6v km.
  3. Altogether 4v+6v=6004v + 6v = 600, so 10v=60010v = 600 and v=60v = 60.
  4. The last 3 hours were at double speed: 2×60=1202 \times 60 = 120 km/h, option A.

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