JAMB 1984 · UME · Q6

A man invested a total of ₦50,000 in two companies which pay dividends of 6%6\% and 8%8\% respectively. How much did he invest at 8%8\% if the total yield is ₦3,700?

Worked solution (try it first)
  1. Let xx be the amount at 8%8\%.
  2. Then 50 000−x50\,000 - x is at 6%6\%.
  3. The yields add up to 3700: 0.06(50 000−x)+0.08x=37000.06(50\,000 - x) + 0.08x = 3700, which is 3000+0.02x=37003000 + 0.02x = 3700.
  4. So 0.02x=7000.02x = 700 and x=700÷0.02=35 000x = 700 \div 0.02 = 35\,000.
  5. He invested ₦35,000 at 8%8\%, option E.

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