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JAMB 1985 · UME · Q25

If f(x−2)=4x2+x+7f(x - 2) = 4x^2 + x + 7, find f(1)f(1).

Worked solution (try it first)
  1. f(1)f(1) means the bracket x−2x - 2 must equal 1, so x=3x = 3.
  2. Put x=3x = 3 into the right-hand side: 4(3)2+3+7=36+104(3)^2 + 3 + 7 = 36 + 10.
  3. So f(1)=46f(1) = 46, option D.

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