JAMB 1985 · UME · Q41

GHIJKLMNGHIJKLMN is a cube of side aa, and HNHN is a diagonal joining opposite corners. Find the length of HNHN.

Worked solution (try it first)
  1. First cross one face: the face diagonal has length a2+a2=a2\sqrt{a^2 + a^2} = a\sqrt2.
  2. HNHN is the hypotenuse of a right-angled triangle with that face diagonal and a vertical edge aa: HN2=2a2+a2=3a2HN^2 = 2a^2 + a^2 = 3a^2.
  3. So HN=a3HN = a\sqrt3, option E.

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