JAMB 1985 · UME · Q43

In the figure, PQPQ is the tangent from PP to the circle QRSQRS, with SRSR a diameter and SRPSRP a straight line. If ∠PQR=θ\angle PQR = \theta and ∠QPR=ϕ\angle QPR = \phi, which of the following relationships is correct?

θφSRQP
Worked solution (try it first)
  1. The angle between the tangent PQPQ and the chord QRQR equals the angle in the alternate segment, so ∠QSR=θ\angle QSR = \theta.
  2. SRSR is a diameter, so ∠SQR=90∘\angle SQR = 90^\circ (angle in a semicircle).
  3. The whole angle SQPSQP is 90∘+θ90^\circ + \theta.
  4. The angles of triangle SQPSQP add up to 180∘180^\circ: θ+(90∘+θ)+ϕ=180∘\theta + (90^\circ + \theta) + \phi = 180^\circ.
  5. So ϕ=90∘−2θ\phi = 90^\circ - 2\theta, option B.

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