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JAMB 1985 · UME · Q5

Find, correct to two decimal places, 100+1100+31000+2710000100 + \frac{1}{100} + \frac{3}{1000} + \frac{27}{10000}.

Worked solution (try it first)
  1. Change each fraction to a decimal: 1100=0.01\frac{1}{100} = 0.01, 31000=0.003\frac{3}{1000} = 0.003 and 2710000=0.0027\frac{27}{10000} = 0.0027.
  2. Add: 100+0.01+0.003+0.0027=100.0157100 + 0.01 + 0.003 + 0.0027 = 100.0157.
  3. To 2 decimal places, look at the third decimal, 5, and round up: 100.02, option A.

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