JAMB 1986 · UME · Q30

At what points does the straight line y=2x+1y = 2x + 1 intersect the curve y=2x2+5x−1y = 2x^2 + 5x - 1?

Worked solution (try it first)
  1. Where they meet, 2x2+5x−1=2x+12x^2 + 5x - 1 = 2x + 1.
  2. Bring everything to one side: 2x2+3x−2=02x^2 + 3x - 2 = 0.
  3. Factorise: (2x−1)(x+2)=0(2x - 1)(x + 2) = 0, so x=12x = \frac12 or x=−2x = -2.
  4. Find yy from the line y=2x+1y = 2x + 1: x=12x = \frac12 gives y=2y = 2, and x=−2x = -2 gives y=−3y = -3.
  5. So the points are (−2,−3)(-2, -3) and (12,2)(\frac12, 2), option A.

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