JAMB 1988 · UME · Q9

If log⁡102=0.3010\log_{10} 2 = 0.3010 and log⁡103=0.4771\log_{10} 3 = 0.4771, evaluate log⁡104.5\log_{10} 4.5 without using logarithm tables.

Worked solution (try it first)
  1. Write 4.5 using 2 and 3: 4.5=92=3224.5 = \frac92 = \frac{3^2}{2}.
  2. So log⁡4.5=2log⁡3−log⁡2\log 4.5 = 2\log 3 - \log 2.
  3. That is 2(0.4771)−0.3010=0.9542−0.30102(0.4771) - 0.3010 = 0.9542 - 0.3010
    =0.6532= 0.6532, option C.

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