JAMB 1989 · UME · Q12

What are the values of yy which satisfy the equation 9y−4(3y)+3=09^y - 4(3^y) + 3 = 0?

Worked solution (try it first)
  1. Let u=3yu = 3^y.
  2. Then 9y=(32)y=u29^y = (3^2)^y = u^2, and the equation is u2−4u+3=0u^2 - 4u + 3 = 0.
  3. Factorise: (u−1)(u−3)=0(u - 1)(u - 3) = 0, so u=1u = 1 or u=3u = 3.
  4. 3y=1=303^y = 1 = 3^0 gives y=0y = 0, and 3y=3=313^y = 3 = 3^1 gives y=1y = 1.
  5. So y=0y = 0 and 1, option D.

Report a problem with this question