QuestionJAMBGeneral Maths1989ObjectiveIndices & standard formQuadratics & their graphsIndices & standard form, Quadratics & their graphs
What are the values of y which satisfy the equation 9y−4(3y)+3=0?
Worked solution (try it first)
Then
9y=(32)y=u2, and the equation is
u2−4u+3=0.
Factorise:
(u−1)(u−3)=0, so
u=1 or
u=3.
3y=1=30 gives
y=0, and
3y=3=31 gives
y=1.
So
y=0 and 1, option D.
Report a problem with this question