JAMB 1989 · UME · Q5

Simplify (64r−63)12\left(\sqrt[3]{64r^{-6}}\right)^{\frac12}.

Worked solution (try it first)
  1. Cube root first: 643=4\sqrt[3]{64} = 4 and r−63=r−2\sqrt[3]{r^{-6}} = r^{-2}, so the inside is 4r−24r^{-2}.
  2. The power 12\frac12 is a square root: (4r−2)12=2r−1(4r^{-2})^{\frac12} = 2r^{-1}.
  3. A negative index means one over: 2r−1=2r2r^{-1} = \frac2r, option D.

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