JAMB 1991 · UME · Q1

Simplify $3\frac13 - 1\frac14 \times \frac23 + 1\frac25$ .

Worked solution (try it first)

Multiply before you add or subtract (BODMAS): $1\frac14 = \frac54$ , and $\frac54 \times \frac23 = \frac{10}{12}$
$= \frac56$ .
Now $\frac{10}{3} - \frac56 + \frac75$ .
The LCD is 30: $\frac{100}{30} - \frac{25}{30} + \frac{42}{30} = \frac{117}{30}$ .
$\frac{117}{30} = 3\frac{27}{30}$
$= 3\frac{9}{10}$ , option B.