JAMB 1991 · UME · Q3

Find, correct to 3 decimal places, (10.05÷15.005)−(0.05×2.05)\left(\dfrac{1}{0.05} \div \dfrac{1}{5.005}\right) - (0.05 \times 2.05).

Worked solution (try it first)
  1. 10.05=20\frac{1}{0.05} = 20.
  2. Dividing by 15.005\frac{1}{5.005} is the same as multiplying by 5.005, so the bracket is 20×5.005=100.120 \times 5.005 = 100.1.
  3. The second bracket is 0.05×2.05=0.10250.05 \times 2.05 = 0.1025.
  4. Subtract: 100.1−0.1025=99.9975100.1 - 0.1025 = 99.9975.
  5. The fourth decimal is 5, so round up: 99.998, option A.

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