JAMB 1991 · UME · Q36

In the figure, PMNPMN and PQRPQR are two secants of the circle MQTRNMQTRN and PTPT is a tangent. If ∠PNR=110∘\angle PNR = 110^\circ and ∠PMQ=55∘\angle PMQ = 55^\circ, find ∠MPQ\angle MPQ.

PQRNMT
Not to scale: the same figure serves both questions.
Worked solution (try it first)
  1. MQRNMQRN is a cyclic quadrilateral.
  2. An exterior angle of a cyclic quadrilateral equals the interior angle opposite it, so ∠QRN=∠PMQ=55∘\angle QRN = \angle PMQ = 55^\circ.
  3. PP, QQ and RR are on a straight line, so in triangle PNRPNR the angle at RR is 55∘55^\circ and the angle at NN is 110∘110^\circ.
  4. The angles add up to 180∘180^\circ: ∠MPQ=180∘−110∘−55∘\angle MPQ = 180^\circ - 110^\circ - 55^\circ
    =15∘= 15^\circ, option D.

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