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JAMB 1991 · UME · Q49

Using the same table, find the percentage of boxes containing at least 5 defective balls each.

Worked solution (try it first)
  1. "At least 5" means 5 or more.
  2. Only the 2 boxes with 4 defective fall short, so 50−2=4850 - 2 = 48 boxes qualify.
  3. As a percentage: 4850×100=96\frac{48}{50} \times 100 = 96, option A.

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