JAMB 1992 · UME · Q13

A man invested a sum of ₦280.00 partly at 5%5\% and partly at 4%4\%. If the total interest is ₦12.80 per annum, find the amount invested at 5%5\%.

Worked solution (try it first)
  1. Let xx be the amount at 5%5\%.
  2. Then 280−x280 - x is at 4%4\%.
  3. The interest adds up to 12.80: 0.05x+0.04(280−x)=12.80.05x + 0.04(280 - x) = 12.8, which is 0.01x+11.2=12.80.01x + 11.2 = 12.8.
  4. So 0.01x=1.60.01x = 1.6 and x=160x = 160.
  5. He invested ₦160.00 at 5%5\%, option D.

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