JAMB 1992 · UME · Q8

Sets & Venn diagrams

If $x = \{\text{all prime factors of 44}\}$ and $y = \{\text{all prime factors of 60}\}$ , the elements of $x \cup y$ and $x \cap y$ respectively are

Worked solution (try it first)

$44 = 2^2 \times 11$ , so its prime factors are $x = \{2, 11\}$ .
$60 = 2^2 \times 3 \times 5$ , so its prime factors are $y = \{2, 3, 5\}$ .
The union takes every element in either set: $x \cup y = \{2, 3, 5, 11\}$ .
The intersection takes those in both: $x \cap y = \{2\}$ .
That is option D.

Report a problem with this question