JAMB 1993 · UME · Q24✱✱

A binary operation ∗* is defined on the set of real numbers by x∗y=xyx * y = x^y for all real values of xx and yy. If x∗2=xx * 2 = x, find the possible values of xx.

Worked solution (try it first)
  1. By the definition, x∗2=x2x * 2 = x^2, so the equation is x2=xx^2 = x.
  2. Bring everything to one side and factorise: x2−x=x(x−1)=0x^2 - x = x(x - 1) = 0.
  3. So x=0x = 0 or x=1x = 1, option A.

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