JAMB 1994 · UME · Q11

Factorize a2x−b2y−b2x+a2ya^2x - b^2y - b^2x + a^2y.

Worked solution (try it first)
  1. Group the terms with a2a^2 and those with b2b^2: (a2x+a2y)−(b2x+b2y)(a^2x + a^2y) - (b^2x + b^2y).
  2. Take out the common factors: a2(x+y)−b2(x+y)=(x+y)(a2−b2)a^2(x + y) - b^2(x + y) = (x + y)(a^2 - b^2).
  3. Factorise the difference of two squares: (x+y)(a−b)(a+b)(x + y)(a - b)(a + b), option D.

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