JAMB 1994 · UME · Q46

Dispersion & cumulative frequency

Find the mean deviation of the numbers 4, 5, 9.

Worked solution (try it first)

The mean is $\frac{4 + 5 + 9}{3} = 6$ .
The distances from 6, ignoring signs, are 2, 1 and 3, which add up to 6.
The mean deviation is $\frac63 = 2$ , option B.

Report a problem with this question