JAMB 1997 · UME · Q1

If (1P03)4=11510(1P03)_4 = 115_{10}, find PP.

Worked solution (try it first)
  1. The place values in base four are 64, 16, 4 and 1, so 1P034=64+16P+0+31P03_4 = 64 + 16P + 0 + 3.
  2. Set it equal to 115: 67+16P=11567 + 16P = 115, so 16P=4816P = 48.
  3. So P=3P = 3, option D.

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