JAMB 1997 · UME · Q16

Find the value of KK if 5+2r(r+1)(r−2)\dfrac{5 + 2r}{(r + 1)(r - 2)} expressed in partial fractions is Kr−2+Lr+1\dfrac{K}{r - 2} + \dfrac{L}{r + 1}, where KK and LL are constants.

Worked solution (try it first)
  1. Multiply through: 5+2r=K(r+1)+L(r−2)5 + 2r = K(r + 1) + L(r - 2).
  2. Put r=2r = 2 so the LL term vanishes: 9=3K9 = 3K.
  3. So K=3K = 3, option A.

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