JAMB 1997 · UME · Q45

Find the median age of the frequency distribution below.

Age	20	25	30	35	40	45
No. of students	3	5	1	1	2	3

Worked solution (try it first)

There are $3 + 5 + 1 + 1 + 2 + 3 = 15$ students, so the median is the $\frac{15 + 1}{2} = 8$ th age.
Running totals: 3 (age 20), 8 (age 25).
The 4th to 8th students are all 25.
So the median age is 25, option B.