JAMB 1997 · UME · Q5

Simplify log⁡296−2log⁡26\log_2 96 - 2\log_2 6.

Worked solution (try it first)
  1. Move the 2 up as a power: 2log⁡26=log⁡2362\log_2 6 = \log_2 36, so the expression is log⁡29636=log⁡283\log_2 \frac{96}{36} = \log_2 \frac83.
  2. Split the fraction: log⁡283=log⁡28−log⁡23\log_2 \frac83 = \log_2 8 - \log_2 3.
  3. log⁡28=3\log_2 8 = 3, so the answer is 3−log⁡233 - \log_2 3, option B.

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