JAMB 1998 · UME · Q49

In a recent zonal championship involving 10 teams, teams XX and YY were given probabilities 25\frac25 and 13\frac13 respectively of winning the gold in the football event. What is the probability that either team will win the gold?

Worked solution (try it first)
  1. Only one team can win the gold, so the two events can't happen together: they are mutually exclusive.
  2. For mutually exclusive events, "either" means add: 25+13=615+515\frac25 + \frac13 = \frac{6}{15} + \frac{5}{15}.
  3. So the probability is 1115\frac{11}{15}, option C.

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