JAMB 1998 · UME · Q8

Given the universal set U={1,2,3,4,5,6}U = \{1, 2, 3, 4, 5, 6\} and the sets P={1,2,3,4}P = \{1, 2, 3, 4\}, Q={3,4,5}Q = \{3, 4, 5\} and R={2,4,6}R = \{2, 4, 6\}, find P∪(Q∩R)P \cup (Q \cap R).

Worked solution (try it first)
  1. Do the bracket first: Q∩RQ \cap R is the elements in both QQ and RR, which is {4}\{4\}.
  2. Then P∪{4}P \cup \{4\} is every element of PP together with 4.
  3. Since 4 is already in PP, this is {1,2,3,4}\{1, 2, 3, 4\}, option B.

Report a problem with this question