JAMB 2000 · UME · Q17✱✱

Which of the graphs represents the solution of the simultaneous inequalities 2x−2≤y2x - 2 \le y and 2y−2≤x2y - 2 \le x?

−2−222A.−2−222B.−2−222C.−2−222D.
Worked solution (try it first)
  1. 2x−2≤y2x - 2 \le y is the region on or above the line y=2x−2y = 2x - 2, through (1,0)(1, 0) and (0,−2)(0, -2).
  2. Rearrange 2y−2≤x2y - 2 \le x: add 2 and divide by 2 to get y≤12x+1y \le \frac12x + 1, the region on or below the line through (−2,0)(-2, 0) and (0,1)(0, 1).
  3. The lines meet at (2,2)(2, 2).
  4. Test the origin: −2≤0-2 \le 0 and −2≤0-2 \le 0 are both true, so the region contains (0,0)(0, 0).
  5. Graph B shades the wedge between these two lines that contains the origin, so the answer is option B.

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