JAMB 2000 · UME · Q24

A frustum of a pyramid with a square base has its upper and lower sections as squares of sides 2 m and 5 m respectively, and the distance between them is 6 m. Find the height of the pyramid from which the frustum was obtained.

Worked solution (try it first)
  1. Let the full pyramid have height HH.
  2. The small pyramid cut off the top has height H−6H - 6 and base side 2 m.
  3. Similar pyramids: side is proportional to height, so 25=H−6H\dfrac{2}{5} = \dfrac{H - 6}{H}.
  4. Cross-multiply: 2H=5H−302H = 5H - 30, so 3H=303H = 30 and H=10H = 10 m, option D.

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