JAMB 2000 · UME · Q48

Find the sum of the range and the mode of the numbers 10, 5, 10, 9, 8, 7, 7, 10, 8, 10, 8, 4, 6, 9, 10, 9, 10, 9, 7, 10, 6, 5.

Worked solution (try it first)
  1. The range is highest minus lowest: 10−4=610 - 4 = 6.
  2. Count the values: 10 appears seven times, more than any other, so the mode is 10.
  3. So the sum is 6+10=166 + 10 = 16, option A.

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