JAMB 2000 · UME · Q9

Simplify 3(2n+1)−4(2n−1)2n+1−2n\dfrac{3(2^{n + 1}) - 4(2^{n - 1})}{2^{n + 1} - 2^n}.

Worked solution (try it first)
  1. Write each power in terms of 2n2^n: 2n+1=2×2n2^{n + 1} = 2 \times 2^n and 2n−1=12×2n2^{n - 1} = \frac12 \times 2^n.
  2. Top: 3×2×2n−4×12×2n=6×2n−2×2n3 \times 2 \times 2^n - 4 \times \frac12 \times 2^n = 6 \times 2^n - 2 \times 2^n
    =4×2n= 4 \times 2^n.
  3. Bottom: 2×2n−2n=2n2 \times 2^n - 2^n = 2^n.
  4. So the fraction is 4×2n2n=4\frac{4 \times 2^n}{2^n} = 4, option C.

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