JAMB 2001 · UME · Q14

The sixth term of an arithmetic progression is half of its twelfth term. The first term is equal to

Worked solution (try it first)
  1. The 6th term is a+5da + 5d and the 12th term is a+11da + 11d.
  2. The 6th is half the 12th, so twice the 6th equals the 12th: 2a+10d=a+11d2a + 10d = a + 11d.
  3. Take a+10da + 10d from both sides: a=da = d.
  4. The first term equals the common difference, option C.

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