QuestionJAMBGeneral Maths2001ObjectiveCalculus (JAMB bridge)Calculus (JAMB bridge)
Evaluate ∫2(2x−3)32dx.
Worked solution (try it first)
Add one to the power:
32+1=35.
Divide by the new power
35 and by 2, the derivative of
2x−3.
So the integral is
2×35×2(2x−3)5/3=53(2x−3)35+k, option D.
Report a problem with this question