JAMB 2001 · UME · Q38

Evaluate ∫2(2x−3)23 dx\displaystyle\int 2(2x - 3)^{\frac23}\,dx.

Worked solution (try it first)
  1. Add one to the power: 23+1=53\frac23 + 1 = \frac53.
  2. Divide by the new power 53\frac53 and by 2, the derivative of 2x−32x - 3.
  3. So the integral is 2×(2x−3)5/353×2=35(2x−3)53+k2 \times \dfrac{(2x - 3)^{5/3}}{\frac53 \times 2} = \frac35(2x - 3)^{\frac53} + k, option D.

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