JAMB 2002 · UME · Q19

Find the equation of the set of points which are equidistant from the parallel lines x=1x = 1 and x=7x = 7.

Worked solution (try it first)
  1. x=1x = 1 and x=7x = 7 are vertical lines, 6 units apart.
  2. The points equidistant from them lie on the vertical line halfway between.
  3. Halfway between 1 and 7 is 1+72=4\frac{1 + 7}{2} = 4.
  4. So the locus is x=4x = 4, option D.

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