JAMB 2002 · UME · Q26

Find the mean of the data 7, −3, 4, −2, 5, −9, 4, 8, −6, 12.

Worked solution (try it first)
  1. Add the positives: 7+4+5+4+8+12=407 + 4 + 5 + 4 + 8 + 12 = 40.
  2. Add the negatives: −3−2−9−6=−20-3 - 2 - 9 - 6 = -20.
  3. So the total is 40−20=2040 - 20 = 20.
  4. There are 10 values, so the mean is 2010=2\frac{20}{10} = 2, option B.

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