JAMB 2002 · UME · Q50

Calculus (JAMB bridge)

The slope of the tangent to the curve $y = 3x^2 - 2x + 5$ at the point $(1, 6)$ is

Worked solution (try it first)

The slope of the tangent is $\frac{dy}{dx} = 6x - 2$ .
At $x = 1$ : $6 - 2 = 4$ , option B.

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