JAMB 2003 · UME · Q16

Find the values of xx and yy respectively if 3x−5y+5=03x - 5y + 5 = 0 and 4x−7y+8=04x - 7y + 8 = 0.

Worked solution (try it first)
  1. Move the numbers across with their signs changed: 3x−5y=−53x - 5y = -5 and 4x−7y=−84x - 7y = -8.
  2. Make the xx terms match: multiply the first by 4 and the second by 3, giving 12x−20y=−2012x - 20y = -20 and 12x−21y=−2412x - 21y = -24.
  3. Subtract the second from the first: y=4y = 4.
  4. Then 3x=5y−5=153x = 5y - 5 = 15, so x=5x = 5.
  5. So x,yx, y are 5,45, 4, option C.

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