JAMB 2003 · UME · Q20

Triangle OPQOPQ in the graph is the solution of the inequalities

xyPQOx + 1 = 0y − x = 0y + x = 0
Worked solution (try it first)
  1. The triangle lies to the right of the vertical line x=−1x = -1, so x+1≥0x + 1 \ge 0.
  2. It lies below the line y=−xy = -x, so y+x≤0y + x \le 0, and above the line y=xy = x, so y−x≥0y - x \ge 0.
  3. Check with the point (−0.5,0)(-0.5, 0) inside the triangle: 0.5≥00.5 \ge 0, −0.5≤0-0.5 \le 0 and 0.5≥00.5 \ge 0.
  4. So it is option B.

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