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JAMB 2003 · UME · Q36

Evaluate ∫23(x2−2x) dx\displaystyle\int_2^3 (x^2 - 2x)\,dx.

Worked solution (try it first)
  1. Integrate: [x33−x2]23\left[\frac{x^3}{3} - x^2\right]_2^3.
  2. At x=3x = 3: 9−9=09 - 9 = 0.
  3. At x=2x = 2: 83−4=−43\frac83 - 4 = -\frac43.
  4. Subtract: 0−(−43)=430 - \left(-\frac43\right) = \frac43, option A.

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