Stepwise
Start practisingPractise

JAMB 2003 · UME · Q41

Find the mean of the distribution below.

Value 0 1 2 3 4
Frequency 1 2 2 1 9
Worked solution (try it first)
  1. Multiply each value by its frequency and add: 0+2+4+3+36=450 + 2 + 4 + 3 + 36 = 45.
  2. Total frequency: 1+2+2+1+9=151 + 2 + 2 + 1 + 9 = 15.
  3. Mean =4515=3= \frac{45}{15} = 3, option B.

Report a problem with this question