JAMB 2003 · UME · Q8

Given U={even numbers between 0 and 30}U = \{\text{even numbers between 0 and 30}\}, P={multiples of 6 between 0 and 30}P = \{\text{multiples of 6 between 0 and 30}\} and Q={multiples of 4 between 0 and 30}Q = \{\text{multiples of 4 between 0 and 30}\}, find (P∪Q)c(P \cup Q)^c.

Worked solution (try it first)
  1. "Between 0 and 30" leaves out 0 and 30, so U={2,4,6,…,28}U = \{2, 4, 6, \dots, 28\}.
  2. P={6,12,18,24}P = \{6, 12, 18, 24\} and Q={4,8,12,16,20,24,28}Q = \{4, 8, 12, 16, 20, 24, 28\}, so P∪Q={4,6,8,12,16,18,20,24,28}P \cup Q = \{4, 6, 8, 12, 16, 18, 20, 24, 28\}.
  3. The complement is the even numbers left over: (P∪Q)c={2,10,14,22,26}(P \cup Q)^c = \{2, 10, 14, 22, 26\}, option C.

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