JAMB 2004 · UME · Q34

The shadow of a pole 535\sqrt3 m high is 5 m. Find the angle of elevation of the sun.

Worked solution (try it first)
  1. The pole is opposite the angle of elevation and the shadow is adjacent, so tan⁡θ=535=3\tan\theta = \frac{5\sqrt3}{5} = \sqrt3.
  2. tan⁡60∘=3\tan60^\circ = \sqrt3, so θ=60∘\theta = 60^\circ, option C.

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