JAMB 2011 · UTME · Q25

Evaluate ∣42−123−1−113∣\begin{vmatrix} 4 & 2 & -1 \\ 2 & 3 & -1 \\ -1 & 1 & 3 \end{vmatrix}.

Worked solution (try it first)
  1. Expand along the first row, with signs +  −  ++ \; - \; +.
  2. The first term is 4×(3×3−(−1)(1))=4×104 \times (3 \times 3 - (-1)(1)) = 4 \times 10
    =40= 40.
  3. The second term is −2×(2×3−(−1)(−1))=−2×5-2 \times (2 \times 3 - (-1)(-1)) = -2 \times 5
    =−10= -10.
  4. The third term is −1×(2×1−3×(−1))=−1×5-1 \times (2 \times 1 - 3 \times (-1)) = -1 \times 5
    =−5= -5.
  5. Add them: 40−10−5=2540 - 10 - 5 = 25, option A.

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