QuestionJAMBGeneral Maths2011ObjectiveMatrices & determinantsMatrices & determinants
Evaluate 42−1231−1−13.
Worked solution (try it first)
Expand along the first row, with signs
+−+.
The first term is
4×(3×3−(−1)(1))=4×10The second term is
−2×(2×3−(−1)(−1))=−2×5The third term is
−1×(2×1−3×(−1))=−1×5Add them:
40−10−5=25, option A.
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