JAMB 2011 · UTME · Q3

Simplify $\dfrac{3\frac23 \times \frac56 \times \frac23}{\frac{11}{15} \times \frac34 \times \frac{2}{27}}$ .

Worked solution (try it first)

Top: $3\frac23 = \frac{11}{3}$ , so the top is $\frac{11}{3} \times \frac56 \times \frac23 = \frac{110}{54}$
$= \frac{55}{27}$ .
Bottom: $\frac{11}{15} \times \frac34 \times \frac{2}{27} = \frac{66}{1620}$
$= \frac{11}{270}$ .
Divide by flipping the bottom: $\frac{55}{27} \times \frac{270}{11}$ .
Cancel 11 into 55 (5) and 27 into 270 (10): $5 \times 10 = 50$ , option D.