Stepwise
Start practisingPractise

JAMB 2011 · UTME · Q30

A solid metal cube of side 3 cm3\text{ cm} is placed in a rectangular tank of dimensions 3 cm3\text{ cm}, 4 cm4\text{ cm} and 5 cm5\text{ cm}. What volume of water can the tank now hold?

Worked solution (try it first)
  1. The tank holds 3×4×5=60 cm33 \times 4 \times 5 = 60\text{ cm}^3 when empty.
  2. The cube takes up 33=27 cm33^3 = 27\text{ cm}^3 of that space.
  3. So the water it can now hold is 60−27=33 cm360 - 27 = 33\text{ cm}^3, option B.

Report a problem with this question