JAMB 2011 · UTME · Q35

Elevation, depression & bearings

A man walks $100\text{ m}$ due West from a point $X$ to $Y$ . He then walks $100\text{ m}$ due North to a point $Z$ . Find the bearing of $X$ from $Z$ .

Worked solution (try it first)

$Z$ is 100 m west and 100 m north of $X$ .
So from $Z$ , $X$ is 100 m east and 100 m south.
Equal amounts east and south means $X$ is exactly south-east of $Z$ .
South-east is $90^\circ + 45^\circ = 135^\circ$ , option B.

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