JAMB 2011 · UTME · Q39Calculus (JAMB bridge)Evaluate ∫01(3−2x) dx\displaystyle\int_0^1 (3 - 2x)\,dx∫01(3−2x)dx.A3B5C2D6Worked solution (try it first)Integrate: [3x−x2]01\left[3x - x^2\right]_0^1[3x−x2]01.At x=1x = 1x=1: 3−1=23 - 1 = 23−1=2.At x=0x = 0x=0: 0.So the integral is 2, option C.Report a problem with this question