JAMB 2011 · UTME · Q7

If log⁡318+log⁡33−log⁡3x=3\log_3 18 + \log_3 3 - \log_3 x = 3, find xx.

Worked solution (try it first)
  1. Combine the logs: adding multiplies and subtracting divides, so the left side is log⁡318×3x=log⁡354x\log_3 \frac{18 \times 3}{x} = \log_3 \frac{54}{x}.
  2. Change to index form: 54x=33=27\frac{54}{x} = 3^3 = 27.
  3. So x=5427=2x = \frac{54}{27} = 2, option B.

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