JAMB 2012 · UTME · Q12

Find the remainder when 2x3−11x2+8x−12x^3 - 11x^2 + 8x - 1 is divided by x+3x + 3.

Worked solution (try it first)
  1. By the remainder theorem, the remainder on dividing by x+3x + 3 is f(−3)f(-3).
  2. f(−3)=2(−27)−11(9)+8(−3)−1f(-3) = 2(-27) - 11(9) + 8(-3) - 1, which is −54−99−24−1-54 - 99 - 24 - 1.
  3. So the remainder is −178-178, option D.

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