JAMB 2012 · UTME · Q23

If ∣53x2∣=∣3545∣\begin{vmatrix} 5 & 3 \\ x & 2 \end{vmatrix} = \begin{vmatrix} 3 & 5 \\ 4 & 5 \end{vmatrix}, find the value of xx.

Worked solution (try it first)
  1. A 2×22 \times 2 determinant is ad−bcad - bc.
  2. The left side is 5×2−3x=10−3x5 \times 2 - 3x = 10 - 3x.
  3. The right side is 3×5−5×4=15−20=−53 \times 5 - 5 \times 4 = 15 - 20 = -5.
  4. So 10−3x=−510 - 3x = -5.
  5. Take 10 from both sides: −3x=−15-3x = -15.
  6. Divide by −3-3: x=5x = 5, option C.

Report a problem with this question